A. Introduction Chemistry is one of the branches of the natural sciences which discussed about the elements, compounds, and natural molecules either organic or non organic, science are the same as the natural sciences the others, both in reviewing, researching and developing the scientific process that is by nature due to conduct research with the system find the problem and resolve the problem. Chemistry is the science that studies matter, composition, and properties of natural surroundings. The material is anything that occupies space and has time. The composition is part of the natural materials that anyone connected with the material. Whereas nature is based typical of such material. Because of the chemistry of the material, the composition and the nature of the specific research is required to be able to differentiate and classify the materials they're based on the resemblance of the nature. …show more content…
( KCLO3 decomposition equation , namely : 2kclo3 ( s ) → 2kcl ( s ) + 3O2 ( g ) ( Mol pic pic = coefficient × mol KCLO3 = 2 × 0.0016 Coefficient KCLO3 2 = 0.0016 mol Mass pic = n × mr = 0.0016 × 74.5 = 0.1192 gram ( Mass o2 = mass KCLO3 - mass pic = 0.2 grams - 0.1192 gram = 0.08 gram ( Mol KCLO3 = mass KCLO3 mr = 0.2 gr 122.5 = 0.0016 mol ( dry Po2 = Ptot - P H2o = 760 mm Hg - 28.35 mmHg = 731.65 mmHg ( Vo2 at STP = Vo2 × Po2 (mmHg) × 273 k 760 (mmHg) TO2 = 0.1197 × 731.65 × 273 k 760 301 = 23908.93187 = 0.1045 L = 0.105 L 228 470 ( P = Po2 = 731.65 mmHg = 0.962697 p.udara 760