Calculations: how did we calculate and determine the mass of magnesium oxide? we Determined the mass of MgO (magnesium oxide) by subtracting the mass of the crucible with lid on from the mass, weight of the crucible with lid, and magnesium oxide. then in order to determine the oxygen mass, we will subtract the mass of the magnesium from the mg oxide to find out the amount of magnesium in the compound, divide the mass of Magnesium ( numbers of grams in one mole of magnesium we did the same way to find the amount of oxygen, where we divided the mass weight of oxygen with the numbers of grams in one mole of oxygen. and lastly in order to determine the empirical formula of magnesium oxide we Used the molar ratio to determined it.

mass of Mg= o.122g mass of magnesium oxide=0.25 mass of magnesium oxide - mass of Mg + mass of O
0.25g= 0.122g + mass of O mass of O = 0.25g- 0.122g = 0.128g moles of Mg = 0.122g x 1 mol of Mg divided 24.30g Mg ( mass of magnesium) = 0.122 mol Mg moles of O = 0.25g O x 1 mol of O divided by 16g of O = 0.25 mol o the ratio = 1:1 there is one mol for mg for one mol of O, therefore there will be 1 atom of mg for 1 mol of oxygen. therefore the empirical formula of magnesium oxide is MgO.

Conclusion: the main purpose of this experiment is to determine the reaction and the magnesium oxide’s empirical formula which is when magnesium reacts with oxygen in the air. By reacting Mg( magnesium ) with O ( oxygen) in the air magnesium oxide will be produced