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Explain How The Surface Area Of The Solute Affect The Rate Of Dissolution

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The guiding question, why do the surface area of the solute, the temperature of the solvent mixed affect the rate of dissolution. To answer this question we used three hypotheses to test; if you increase the surface area than the rate of dissolution increases, If you increase the temperature of solvent then the rate of diffusion increases, If you increase the amount of agitation then the rate of dissolution. We predicted that changing the stress, surface area, temperature, and stirring in a controlled experiment it would forward the rate of dissolution. Based on the background on making lemonade, when sugar is added to water and stirred the sugar (solute) dissolves quickly, when sugar (solute) is fine, the temperature is raised, and agitation is increased the solution dissolves at an increased rate. …show more content…

In hypothesis one we added surface area (stress) to the solute. In this experiment we used 1 gram sample of medium crystals and 1 gram sample of fine crystals. We put the 2 samples into separate beakers and added 40 mL of water to each beaker at the same time. During observations, both fine and medium crystals sank to the bottom of the water. The finer crystals had small bubbles rising to the surface of the liquid and the water (solvent) dissolved more fine crystals (solute) than medium crystals in 10 minutes. In our results we found that the solute with less surface area dissolves into a solvent faster than a solute with more surface area. We can now confirm that the stress of surface area on a solute affects the rate of dissolution, the more surface area of a solute the rate of dissolution increases. This is proven through the results of our first hypothesis

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Our hypothesis was partially correct, the property changing substances did have the weakest coherency with the lowest drop counts of 23(carbonated), and 14(soap), and pure water did have the strongest bond. What we also found was the the salt also dampened the liquid’s ability to hold onto a penny in large volumes, as all the different salts had a drop average of 24(28x2 & 16), five less than Tap water’s drop count (30). This led us to conclude that pure water has the strongest bond and that all foreign materials weaken the coherency of water. This evidence has led me to believe that similar substances are attracted and are more coherent towards themselves, in this case the water pieces get separated and generally less connected on a really small level due to the obstruction of foreign objects, this is why the different salts perform better than the huge air bubbles or the slippery properties of soap since the latter is more obstructive and the former dissolves with the water and blocks less. When studying a few other groups’ conclusions and data we did indeed find differences: some groups had differing data where a solution had better coherence than water itself which led to differing conclusions.

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Introduction: In this assignment, I will be doing two experimentations on examining the impact of temperature on the Alka-Seltzer’s response time. The first experimentation that I will be doing involves some water that is room temperature. The second experimentation that I will be doing involves some water that is very hot. If I want to be able to figure out the impact of the temperature on water, I will have to document the time it will take for the Alka-Seltzer to go into solution.

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The results do not support the hypothesis that a higher surface area to volume ratio would result in sulphuric acid being diffused into the agar cubes in the shortest amount of time. This is evident in the results as the exact opposite to what was predicted occurred. Instead of the smallest cube with the largest surface area to volume ratio of 1cm3 having the quickest diffusion rate, it conversely took the longest at 0.092 cm3 per second, whilst the 2cm3 cube with 0.0384 cm3 per second took the least amount of time. This directly refutes the hypothesis. There was also no consistent trend evident in the results.

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The dissolution of the salt could be reversed by evaporating the water as shown in part one of the experiment, just as evaporating the water could be reversed by adding water as demonstrated in part two of the

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During the experiment, observations were made of their color, mass, height, and width. This data shows percent mass change of the gummy bear and how the gummy bear was affected by the salt water. It also displays how the height and the width of the gummy bear changed because of the salt water, which made the gummy bear more compact. The more salt that was added to the distilled water, the more compact it was, however, if there was not a lot of salt in the mixture, it became large and fragile. The mass of the gummy bear was increased as a result of less salt being added with the distilled water.

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In this lab we used two processes called Diffusion and Osmosis. Diffusion is the movement of molecules from areas of high concentration to areas of low concentration. Diffusion is a process that requires no energy and involves smaller non-polar molecules. In Figure 1 you can see the molecules spreading throughout the glass from the area of high concentration, so that the areas with low concentration are filled evenly as well. The other process was osmosis.

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Exploration Title: Effect of Temperature on rate of Osmosis Submitted By: Abdulkarim Kamal Date Submitted: October 19th 2015 Subject: Biology HL Teacher: Mr. Nick   Aim: This is an investigation to determine the relation between temperature of a solution (sucrose) and the rate of osmosis Scientific Context: Osmosis is defined a passive transport process in which a fluid diffuses across a semi-permeable membrane, from an area of high solute concentration to an area of low solute concentration and vice-versa. There are various factors that could potentially influence the rate of osmosis; these factors include volume, concentration, and temperature. If all external factors that may interfere with rate of osmosis are controlled, the results will show equal amounts of fluid on both sides of the barrier (membrane); this is known as an “isotonic” state.

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What is the effect of surface area to volume ratio on the rate of diffusion of the colour from the agar jelly cube? INTRODUCTION: Diffusion is the movement of spreading particles from high concentration to low concentration in an environment such as a cell. This major procedure is used in cells to source them with nutrients, water, oxygen, and to transport unwanted wastes such as carbon dioxide out of the cell or to different cellular organelles.

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The developing solution was poured into a tank and was tightly covered with a glass lid, and the tank was allowed to be saturated to ensure that the solution was equilibrated in the gas phase. Silica plate for TLC analysis: A horizontal line was drawn with a pencil on the plate and it was about 1 cm above the bottom of the plate. The horizontal line was drawn faintly so as to avoid damaging the silica gel on the plate. On the horizontal line, two marks were made and one was named A and the other B. These marks were made towards the centre of the plate at a distance apart because when spots are made at the edge of a plate, the result would be an improper travel of the samples as the solvent advances on the plate.

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