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The control in the experiment is water. Units used while timing the productivity of gas from an Alka-Seltzer tablet in different temperatures is, seconds. In order to find out if temperature controls the rate of chemical reaction, whether hot water is a more effective way to make the gas produce at a faster speed, it would be necessary to compare the results of different temperatures at the end of each trial. In order to do this the scientists will measure the volume of gas that is produced within a 10 second interval time after the tablet begins to react.
We then obsevered the two slides for number of cells as well as for food vacuoles inside a cell using a microscope at times of 0,5,10,20, and 30 minutes. Results The following graphs show the results of this experiment. The tetrahymena sample that was introduced to concentrated tobacco had a lower cell/vacuole ratio than the tetrahymena sample that was not exposed to
Additionally, it was difficult obtaining a piece of rhubarb that was thin and particularly red, therefore the effect could not be best observed in the cells. Part B: Design your own experiment Parts of this practical were taken and slightly altered from the following link http://www.markedbyteachers.com/gcse/science/investigate-the-effect-of-surface-area-on-osmosis-in-potato-tissue.html Aim: To observe the effect different surface area: volume ratios have on osmosis in potato tissue. Hypothesis: If the potato has a larger surface area: volume ratio, the quicker osmosis will take place and the larger the mass will be at the end of the experiment, therefore the difference in mass of the potatoes from the start of the experiment to the end of the experiment will be larger. Additionally, the potato pieces left in a saltwater solution will decrease in mass, whereas the pieces left in water will increase in mass.
a. Water boils to produce steam at 100 C (212 F) b. Water produces gas with sodium metal c. Water and oil separate when combined d. Water dissolves sugar 22. In the experiment, students put brine shrimp in water with different concentration of salt and counted the number. Which of the following changes to the experiment will increase confidence in the validity of the result? a. Count the number of dead brine shrimp instead of living brine shrimp b. Add more brine shrimp to the water with the highest salt concentration c.
The gummy bear's mass and volume will increase while the density of the gummy bear would decrease after it is put into water overnight. (#)This lab experimented to figure out wah changes would take to the gummy bear’s mass, volume, and density after sitting in a cup of water overnight. To do this the gummy bear's dimensions and weight was taken on the first day, along with its density and then the gummy bear was placed and water. When the gummy bear was taken out of the water on day two, the dimensions, weight, and density were taken again, and the difference between the two days was found. (#1)
Gummy Bear Breast Implants Boston Procedure Gummy Bear Breast Implants in Boston Individuals in Boston who are unhappy with the way their breasts look may want to consider a breast augmentation (augmentation mammoplasty) with gummy bear, also referred to as form stable, breast implants. Dr. Christopher J. Davidson is a renowned, Board Certified plastic surgeon in the Boston area: He offers his patients form stable implants as a means to assist them in attaining the size breasts they desire. Common Reasons Individuals Choose an Augmentation with Gummy Bear Implants in Boston Via an augmentation using gummy bear implants, Dr. Davidson can: Give his patients the breasts they desire; thus, boosting their self-esteem.
In this lab we used two processes called Diffusion and Osmosis. Diffusion is the movement of molecules from areas of high concentration to areas of low concentration. Diffusion is a process that requires no energy and involves smaller non-polar molecules. In Figure 1 you can see the molecules spreading throughout the glass from the area of high concentration, so that the areas with low concentration are filled evenly as well. The other process was osmosis.
This experiment demonstrated water density because the cold water moved beneath the hot water, because it is denser. 5. Was your hypothesis supported or refuted? Explain.
In this experiment, the question that was asked was, are elephants afraid of mice? The hypothesis is if a mouse is placed near an elephant, then the elephant will be frightened. The experimenters traveled to an African safari to perform the experiment with their test subjects (an African elephant and a white mouse). They hid the mouse in elephant dung and rolled over the dung whenever elephants passed by. At first there was speculation that the elephants might have been startled by the moving dung.
Exploration Title: Effect of Temperature on rate of Osmosis Submitted By: Abdulkarim Kamal Date Submitted: October 19th 2015 Subject: Biology HL Teacher: Mr. Nick Aim: This is an investigation to determine the relation between temperature of a solution (sucrose) and the rate of osmosis Scientific Context: Osmosis is defined a passive transport process in which a fluid diffuses across a semi-permeable membrane, from an area of high solute concentration to an area of low solute concentration and vice-versa. There are various factors that could potentially influence the rate of osmosis; these factors include volume, concentration, and temperature. If all external factors that may interfere with rate of osmosis are controlled, the results will show equal amounts of fluid on both sides of the barrier (membrane); this is known as an “isotonic” state.
In this practical agar jelly cubes will be used to represent a cell. AIM: To model diffusion in a practical form and investigate the effect of surface area to volume ratio. HYPOTHESIS: It is hypothesised the smaller the cube the quicker and bigger the rate of diffusion will be and with a larger cube there will be a smaller percentage of diffusion due to its bigger volume.
By using the same mass of potato slices and putting them in different concentration of solutions for a specific amount of time will tell us how the concentration changes the mass of the potato slice. Therefore changing the rate of osmosis. Hypothesis: I predict that, if the piece of potato was put into a solution that has a high concretion of sucrose then the potato slice would lose mass as it would lose water from its cells because the water is moving out of the cell from a high concentration to a low concentration of water through a semi- permeable membrane. The cell is hypotonic and the solution is hypertonic.
Two of the same types of plants were used, in order for the results to be reliable. One of the plants was labelled DISTILLED whereas the other was ACIDIC, so the results don’t get mixed. The DISTILLED plant was used as a controlled variable, where normal spring water was used (pH 7.3) The ACIDIC plant was the one the experiment had taken place on, this was where lemon water was used (pH 2.0) Throughout the experiment pictures were taken, so one will be able to notice the colour change on the acidic plants, as it had started to slowly die. With both plants you are able to notice that they had both started to grow flowers, but more the spring watered plant than that on the lemon juice watered one. The results of the plant growth was recorded to we would be able to notice the amount it had grown, this would be the water compared to lemon juice.
Biology Design Practical Joshua Edwards What are effects of the volume of a potato and the amount of weight it loses when placed in salt solution? Introduction This design practical uses a potato’s surface area to volume ratio to see what affects it has on osmosis in different concentrations. Osmosis is the movement of water molecules through a cell membrane into an area of a higher solute concentration. The movement goes the way of the solvent with more solute because the lower solute concentration is drifting through balancing the ratio of solute per solvent (En.wikipedia.org, 2018).
Conclusion In conclusion my hypothesis was right and the wet bread grew the most (and only) mould. I can logically assume that the more moisture the bread has, the more mould it will grow. This was a fair test because each of the bread pieces had equal time to grow. The End In this experiment the conductor finds out that mould needs moisture thus needs to be included to conduct the experiment.