Throughout chapters seven through twelve, A lot of information has been given to us students. Inorder to pull this information together we are given labs and Pogil packets that explain exactly what is happening. Three of these labs or activities that have given me a better understanding of our topics. The labs “Double Replacement Reactions” and “Reactivity of Metals” helped me figure out how to find the the products of a chemical reaction. The Pogil activity “Limiting and Excess Reactants” helped me understand how to calculate the amounts of reactants and products in a chemical reaction. The lab “Double Replacement Reactions” was not only a very interesting lab, but also a very informative one. The big question that this lab helped me answer …show more content…
This lab taught me how to find the products of single replacement reactions by switching the positive ion in a compound with another ion. Before a reaction can take place the ion replacing must have a higher activity than the ion being replaced. This can be determined by using a reactivity chart, but for this lab we did not have one. For this lab, Instead of using a activity chart, we took small pieces of magnesium, zinc, and copper and added them to different solutions. After watching for which metals caused reactions within their test tubes, we listed which elements were more active than others. We came to the conclusion that the metals listed from least active to most active were silver, copper, lead, zinc, magnesium, sodium, and potassium. Our data and claim is supported by the article from https://chem.libretexts.org/Reference/Reference_Tables/Electrochemistry_Tables/P3%3A_Activity_Series_of_Metals, which sataes that when a metal is put into a solution of a metal salt, it may be more stable for the lone metal to switch places with the positive ion that is within the …show more content…
This activity answered the question of how to find the amounts of products and reactants within a chemical reaction. The amount of reactant produced by a chemical equation can be found by finding the limiting reactant. In order to find the limiting reactant, one must use stoichiometry to find which product produces the least amount of the reactant. The lowest answer is the limiting reactant. This activity had many models to help explain what the limiting reactant is and how it can be found. One model that really helped me to understand limiting reactants was the assembling a race car model. For this model, each race car requires one body, four wheels, one engine, and three cylinders. Then there is a question that gives you fifteen cylinders and an unlimited supply of the rest of the parts and asks you how many cars can be built. Since every car needs three cylinder only five cars can be built. This in turn means that the “limiting part” is the cylinder. According to the article “Excess and Limiting Reagents” the limiting reactant limits the amount of product