Lab Report Stoichiometry And

Stoichiometry is the determination of the proportions in which elements or compounds react with one another. Chemical equations require the mole, mass, and atom ratios to remain constant. A double replacement reaction can occur when two ionic compounds are placed in a solution. The equation used in this experiment is a double replacement reaction because 2 pairs of elements react and swap element pairs (A+X + B+Y→B+X + A+Y). When these ionic compounds react and are filtered, a combination of ions will be insoluble in water, so it filters out of the solution. To produce the 2.00 grams of the compound in this experiment, the chemical equation must be balanced, the precipitate must be identified, each reactant and products molar masses should

A digital scale should be used to precisely measure the grams of the needed masses, and 25 mL of water should be poured into 2 beakers, each getting 25 mL. Place a flask under a ring stand containing a funnel with an 11 cm filter paper. Each measured reactant goes into one of the beakers, and then these two beakers’ contents are combined. Pour the mixture of the two reactants slowly and intermittently into the funnel until the mixture is gone and it has filtered all the way through the filter paper and into the

The needed mass for reactant A was 3.52 grams and the needed mass for reactant B was 2.12 grams. The moles of product C (CaCO3) were also required to have been calculated using mass- to- mole conversion, but the mass was already established, so its mass was not calculated.
Results
Calculations used to determine the percent error
2.3 g CaCO3 - 2.00 g CaCO3 2.00 g CaCO3 x 100 = 15 %
Reactants A and B’s masses were not similar, but the numbers were also not drastically different. Obviously, product C’s solution is different because moles were calculated as opposed to a mass. Percent error was also calculated, using the masses of the filter paper and the precipitate. To determine the mass of the precipitate, measure the dry filter paper containing the precipitate, and then subtract the mass of the individual filter paper from the mass of the dry filter paper and the precipitate. Once the mass of the precipitate is determined, it is used in the percent error equation, seen above. The predicted mass is subtracted from the mass of the precipitate, divided by the predicted mass, and then multiplied