.1-amEr
(c) Gram molecular mass of HNO3 = Mass of 1-molecule of HNO3x NA
= 63 amu x NA = 63 gm X NA = 63 gram
NA
Solved Example-4:Find out the mass of carbon -12 that would contain 1.0 x1019carbon-12 atoms. Solution : Mass of 6.022 x1023 carbon-12 atoms = 12 g
Mass of 1.0 x1019 carbon-12 atoms = 12x1x10 19 g
6.022 x1023 = 1.99 x10-4g
Solved Example-5: How many molecules are present in 100 g sample of NH3?
Solution : Molar mass of NH3 = (14 + 3) g mol-1 = 17 g mol-1
17 g sample of NH3 contains 6.022 x1023 molecules
Therefore, 100 g sample of NH3 would contain = 6.022x10 23 x 100g molecule
I 7g '
= 35.42x1023 g molecules.
= 3.542x1024 g molecules.
Solved Example -6 : Molar mass of 0 is 16 g mot-1. What is the mass of one atom and one molecule of oxygen? Solution : Mass of 1 mol or 6.022 x1023 atoms of 0 = 16 g
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(b) Calculate the volume occupied by 8 g of sulphur dioxide at STP[S = 32; 0 =