%addcontentsline{toc}{section}{Activity 5.4} section*{Activity 5.4}
egin{enumerate} item I divide the class into pairs. item I gave the learners the following exercises in Grade 10 (Set 7).\ extbf{Simplify the following expressions:}\ egin{enumerate}[(a)] egin{minipage}{0.60 extwidth} item $frac{4m}{n^{-3}} imes frac{3}{10m^2 n^2}$ \ \ item $frac{2^x + 2^{x+1}}{2^x}$ \ \ item $frac{3^a - 3^{a-1}}{3^{a+2} - 3^{a+1}}$ \ \ item $frac{5^x.2^x}{10^x}$ \ \ item $frac{7^{x+1} - 7^{x}}{6.7^{x}}$ \ \ item $frac{6^x.3^{-1}}{36^{-x+1}}$ end{minipage}% egin{minipage}{0.60 extwidth} %egin{enumerate}[{11.}] item $frac{5^{x+2} - 5^{x+1}}{5^{x+1}}$ \ \ item $frac{3^x - 3^{x-2}}{8.3^x}$ \ \ item $frac{2.2^{n+1} - 2^{n}}{3.2^{n-1}}$ \ \ item
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From this day I learned that we should sometimes group learners such that they can discuss the language of mathematics. I observe that learners can learn better if they work with their mates because they feel free to express their view to their mates than a teacher. Cooperative learning is a powerful strategy which we can use to engage learners in doing mathematics. When I walk around I saw that they were debating on some conceptual errors and fortunately the one who was believing the errors turn out to understand how it is wrong. Most of the learners cannot believe that $7^{x+1} - 7^{x}$ is equal to $7^{x}(7 - 1) = 6 imes 7^{x}$. From the idea that they know that $x^2 - x$ is equal to $x(x-1)$, I was able to help to construct that knowledge. I also realize that complicated problems are always stressing the child, for this reason, we must first help them to solve the easy problem, once they are familiar with them then we can include the complicated ones. Cooperative learning promotes a positive relationship and communication