Mastering Acetic Acid Equilibrium: Exam Prep and pH Calculation
School
North Carolina State University**We aren't endorsed by this school
Course
CH 101
Subject
Chemistry
Date
Dec 11, 2024
Pages
1
Uploaded by DrKoupreyMaster1164
Final Exam●Where: in class, Dabney 222●Format: multiple choice●When: Tuesday, December 12, 2023●Time: 3:30-6:00 PM●Anywhere from 90-120 questionsIn Class ExerciseYou have a 1.0 M solution of acetic acid, H_2H_3O_2 (Ka = 1.8x10^-5). Calculate the equilibriumconcentration of acetic acid, H_3O^+, acetate, and the pH.HC_2H_3O_2 (aq) + H_2O (l) → H_3O^+ (aq) + C_2H_3O_2^- (aq)AcidBaseConj. AcidConj. BaseAcid (-x)BaseConj. Acid (+x)Conj. Base (+x)I1 M00C-x+x+xE1 - x MxxKa = 1.8x10^-5 = [H_3O^+][C_2H_3O_2^- ]/[HC_2H_3O_2] = x^2/1-x●1.8x10^-5 = x^2, assume x <<< 1●x = 0.00424 M●-log(0.00424) = pH = 2.37
