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Understanding Limit Points and Compact Sets in Real Analysis
Understanding Limit Points and Compact Sets in Real Analysis
School
Southern New Hampshire University
*
*We aren't endorsed by this school
Course
MAT 470
Subject
Mathematics
Date
Dec 11, 2024
Pages
3
Uploaded by Dejahnc1998
MAT 470 β Module 3 Assignment
Southern New Hampshire University
Dejah Crews-Siler
November 13, 2024
3.2.2
Let
? = {(β1)
π
+
2
π
: ? = 1, 2, 3, β¦ } ??? ? = {? β ?: 0 < ? < 1}
= {β1 + 2, 1 +
2
2
, β1 +
2
3
, 1 +
2
4
, β1 +
2
5
, 1 +
2
6
,
. . . . . .
}
= {1,2, β0.33,1.5, β0.60,1.33}
a)
What are the limit points?
The limit points are -1 and 1
b)
Is the set open? Closed?
Set A is not a closed set. Set A does not have interior points, and therefore is not an open
set. Set A is not open or closed set.
c)
Does the set contain any isolated points?
1 is an isolated point in the set of A
d)
Find the closure of the set.
?
Μ
= ? βͺ ?(?) = {(β1)
π
+
2
?
: ? = 1, 2, 3, β¦ } βͺ {β1}
3.3.2
a)
N
N is a set of all natural numbers and is not compact
b)
? β© [0,1]
Having a set of rational numbers that are intersected with
[0,1] = ? β© [0,1]
this making
? β©
[0,1]
not compact
c) The cantor set
A cantor set has an intersection that is of a closed set, because there is a subset of [0,1] it makes
it bounded making cantor set compact.
d)
{1 +
1
2
2
+
1
3
2
+. . . +
1
π
2
: ? β π}
Because
lim
πββ
(1 +
1
2
2
+
1
3
2
+. . . +
1
π
2
) = β
(
1
π
2
)
β
π=1
it is convergent and therefore the sum isnβt a
set, and it is not compact.
e)
{1,
1
2
,
2
3
,
3
4
,
4
5
, . . . }
Because
lim
πββ
(
π
π+1
) = 1
this makes the only limit point a given set in which this limit is between
0 and 1 that makes it bounded. Therefore, this set is compact.
3.4.2
Does there exist a perfect set consisting of only rational numbers?
- Having a set of all rational numbers that are between [0,1]. We can take
? = ? β© [0,1]
, this set
contains all limit points. Irrational numbers in an interval [0, 1] are the limit point of the set
? β©
[0,1]
. In this set every point is considered a lime point because between having 2 rational
number.
3.5.5
Show that it is impossible to write where for each
? β π, ?
π
is a closed set containing no
nonempty open intervals.
We assume
?
π
β?? ?? ????? π????π??. πΏ?? π
π
= β
?
π
π
π=1
?
π
is closed and
?
π
π
π? ????
3.5.9
Decide whether the following sets are dense in R, nowhere dense in R, or somewhere in
between.
a)
? = ? β© [0. 5]
?π??? ?
= [0,5] ?βπ?β π? ? ???????? ???? π???????, ?βπ? ????? ?β?? π? ??? ??? ?? ?????
b)
? = {
1
π
: ? β π}
Closure of given set
? = {
1
π
: ? β π} βͺ 0
, which does not contain any non open interval
therefore it is not dense
c)
The set of irrationals
Let the interval
?, ? β ? ?β??? ? < ? ?β?? ?β??? ??π?? π????π???? ?????? ? β
π
π
???β ?β?? ? < ? < ?
d)
The Cantor set
This set is nowhere dense, that if C contains an open interval (a, b) then
|?| β₯ |?, ?| = |?, ?|
?? ?? ???? ?β?? |?| = 0. ?β??????? ?βπ? ??? ?????? ?????π? ??? ???? π???????.