Understanding Limit Points and Compact Sets in Real Analysis

School
Southern New Hampshire University**We aren't endorsed by this school
Course
MAT 470
Subject
Mathematics
Date
Dec 11, 2024
Pages
3
Uploaded by Dejahnc1998
MAT 470 – Module 3 AssignmentSouthern New Hampshire UniversityDejah Crews-SilerNovember 13, 2024
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3.2.2Let ? = {(βˆ’1)𝑛+2𝑛: ? = 1, 2, 3, … } ??? ? = {? ∈ ?: 0 < ? < 1}= {βˆ’1 + 2, 1 +22, βˆ’1 +23, 1 +24, βˆ’1 +25, 1 +26,. . . . . .}= {1,2, βˆ’0.33,1.5, βˆ’0.60,1.33}a)What are the limit points?The limit points are -1 and 1 b)Is the set open? Closed?Set A is not a closed set. Set A does not have interior points, and therefore is not an open set. Set A is not open or closed set. c)Does the set contain any isolated points?1 is an isolated point in the set of A d)Find the closure of the set. ?Μ…= ? βˆͺ ?(?) = {(βˆ’1)𝑛+2?: ? = 1, 2, 3, … } βˆͺ {βˆ’1}3.3.2a) NN is a set of all natural numbers and is not compact b) ? ∩ [0,1]Having a set of rational numbers that are intersected with [0,1] = ? ∩ [0,1]this making ? ∩[0,1]not compact c) The cantor set A cantor set has an intersection that is of a closed set, because there is a subset of [0,1] it makes it bounded making cantor set compact. d){1 + 122+132+. . . +1𝑛2: ? ∈ 𝑁}Because limπ‘›β†’βˆž(1 +122+132+. . . +1𝑛2) = βˆ‘(1𝑛2)βˆžπ‘›=1it is convergent and therefore the sum isn’t a set, and it is not compact.
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e) {1,12,23,34,45, . . . }Because limπ‘›β†’βˆž(𝑛𝑛+1) = 1this makes the only limit point a given set in which this limit is between 0 and 1 that makes it bounded. Therefore, this set is compact.3.4.2Does there exist a perfect set consisting of only rational numbers? - Having a set of all rational numbers that are between [0,1]. We can take ? = ? ∩ [0,1], this set contains all limit points. Irrational numbers in an interval [0, 1] are the limit point of the set ? ∩[0,1]. In this set every point is considered a lime point because between having 2 rational number. 3.5.5Show that it is impossible to write where for each ? ∈ 𝑁, ?𝑛is a closed set containing no nonempty open intervals. We assume ?π‘›β„Ž?? ?? ????? 𝑖????𝑖??. 𝐿?? 𝑉𝑛= ⋃?𝑖𝑛𝑖=1?𝑖is closed and ?𝑖𝑐𝑖? ???? 3.5.9Decide whether the following sets are dense in R, nowhere dense in R, or somewhere in between.a)? = ? ∩ [0. 5]?𝑖??? ?= [0,5] ?β„Žπ‘–?β„Ž 𝑖? ? ???????? ???? 𝑖???????, ?β„Žπ‘–? ????? ?β„Ž?? 𝑖? ??? ??? ?? ????? b)? = {1𝑛: ? ∈ 𝑁}Closure of given set ? = {1𝑛: ? ∈ 𝑁} βˆͺ 0, which does not contain any non open interval therefore it is not dense c)The set of irrationals Let the interval ?, ? ∈ ? ?β„Ž??? ? < ? ?β„Ž?? ?β„Ž??? ??𝑖?? 𝑖????𝑖???? ?????? ? βˆˆπ‘…πœƒ???β„Ž ?β„Ž?? ? < ? < ?d)The Cantor set This set is nowhere dense, that if C contains an open interval (a, b) then |?| β‰₯ |?, ?| = |?, ?|?? ?? ???? ?β„Ž?? |?| = 0. ?β„Ž??????? ?β„Žπ‘–? ??? ?????? ?????𝑖? ??? ???? 𝑖???????.
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