```{r}LRT_vec = replicate(10000, LRT_func2())head(LRT_vec)```(iii)```{r}hist(LRT_vec, freq = FALSE, breaks = 50, col = "green")```(iv)```{r}samples = rchisq(100000, df = 1)density = density(samples)hist(LRT_vec, freq = FALSE, breaks = 50, col = "green")lines(density, col = "red", lwd = 3)```## (c)The sample size n would affect the closeness of the histograms and the chi-square(df=1) density. For this case(n=5), which is relatively small, there is some biases between two density curve. By CLT, if n approach to infinity, the LRT will converge to chi-square density with df=1, then the histogram and the chi-square density will match more perfectly.