ANOVA

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School

University of Economics Ho Chi Minh City**We aren't endorsed by this school

Course

BA 101

Subject

Statistics

Date

Dec 16, 2024

Pages

Uploaded by CoachSteelPolarBear38

20. In the Excel file Cell Phone Survey, test the hypothesis that the mean responses for Value for the Dollar and Customer Service do not differ by gender H0: There is no difference in the mean responses for "Value for the Dollar" and "Customer Service" based on gender. H1: There is a difference in at least one of the mean responses (either "Value for the Dollar" or "Customer Service") based on gender.Using a one-way ANOVA., we test the hypothesis that there is no difference between the means of "Value for the Dollar" and "Customer Service" by gender, at a 95% confidence level. The p-values for "Value for the Dollar" and "Customer Service" are 0.853 and 0.119, respectively. Since both p-values are greater than the significance level of 0.05, we fail to reject the null hypothesis for both variables. This indicates that there is no significant difference between the mean responses for "Value for the Dollar" and "Customer Service" based on gender. 21. Using the data in the Excel file Cell Phone Survey, apply ANOVA to determine if the mean response for Value for the Dollar is the same for different types of cell phones. H0: There is no difference in the mean responses for “Value for the Dollar” based on types of cell phones H1: There is a difference in the mean responses for “Value for the Dollar” based on types of cell phones ANOVA Sum of Squares df Mean Square F Sig. Customer Service Between Groups 2.257 1 2.257 2.509 .119 Within Groups 44.974 50 .899 Total 47.231 51 Value for the Dollar Between Groups .032 1 .032 .034 .853 Within Groups 46.660 50 .933 Total 46.692 51

ANOVA Value for the Dollar Sum of Squares df Mean Square F Sig. Between Groups 5.261 2 2.631 3.111 .053 Within Groups 41.431 49 .846 Total 46.692 51 Using one-way ANOVA test, we test the hypothesis that there is no difference in the means of “Value for the dollar” by types of cell phones, at a 95% confidence level. The p-value for “Value for the dollar” is 0.053 which is larger than 0.05. We fail to reject the null hypothesis for the variable. This indicates that there is no difference in the mean responses for “Value for the Dollar” bases on types of cell phones. 31. Using the data in the Excel file Freshman College Data, use ANOVA to determine whether significant differences exist in the mean retention rate for the different colleges over the 4-year period. Second, use ANOVA to determine if significant differences exist in the mean ACT and SAT scores among the different colleges. H0: There is no differences in the mean of “1styear retention rate” by colleges over the 4-year period. H1: There is a difference in the mean of “1styear retention rate” by colleges over the 4-year period. ANOVA 1st year retention rate Sum of Squares df Mean Square F Sig. Between Groups .274 10 .027 10.774 .000 Within Groups .084 33 .003 Total .358 43 Using one-way ANOVA test, we test the hypothesis that there is no difference in the means of “Value for the dollar” by types of cell phones, at a 95% confidence level. The p-value for “Value for the dollar” is 0.000 which is smaller than 0.05. We reject the null hypothesis for the variable.

This indicates that there is a significant difference in the mean responses for “Value for the Dollar” bases on types of cell phones. H0: There is no difference in the mean responses for "Average ACT" and "Average SAT" based on colleges. H1: There is a difference in at least one of the mean responses (either "Average ACT" or "Average SAT") based on colleges. ANOVA Sum of Squares df Mean Square F Sig. Avg ACT Between Groups 242.979 10 24.298 110.611 .000 Within Groups 7.249 33 .220 Total 250.228 43 Avg SAT Between Groups 399025.295 10 39902.529 126.994 .000 Within Groups 10368.830 33 314.207 Total 409394.125 43 Using one-way ANOVA test, we test the hypothesis that there is no difference in the mean response of “Average ACT” and“Average SAT” among differences colleges. The p-value of “Average ACT” and “Average SAT” are both 0.000, which are lower than 0.05. Therefore, we reject the null hypothesis for the variables. This indicates that there are differences in the mean of “Average ACT” and “Average SAT” by different colleges.