Mml3.6
.docx
School
George Mason University**We aren't endorsed by this school
Course
MATH 114
Subject
Mathematics
Date
Dec 21, 2024
Pages
19
Uploaded by ProfessorTeamPuppy102
@ study Plan Practice - Rathnadeepika Putla - Work - Microsoft Edge & https://mylab.pearson.com/Student/PlayerPractice.aspx?closeUrl=StudyPlanRecommer Analytic Geometry/ Calculus | d Given y = f(u) and u = g(x), find % =f'(g(x))g’ (). 1 y=4u+7, u= [Eths @ That's i Correct answe Your answer:
@ study Plan Practice - Rathnadeepika Putla - Work - Microsoft Edge & https://mylab.pearson.com/Student/PlayerPractice.aspx?closeUrl=StudyPlanRecommer Analytic Geometry/ Calculus | d Given y =f(u) and u = g(x), find % =f'(g(x))g’(x) for the following functions. y=sinu,u=5x+2 @ That's i Correct answe Your answer:
@ study Plan Practice - Rathnadeepika Putla - Work - Microsoft Edge & https://mylab.pearson.com/Student/PlayerPractice.aspx?closeUrl=StudyPlanRecommer Analytic Geometry/ Calculus | d Given y =f(u) and u = g(x), find % =f'(g(x))g’ (x)- @ That's i dy _ ‘ 3 | Correct answe | > (sinx)cosx‘ 15u5 ‘ Your answer:
Wrong form?
@ study Plan Practice - Rathnadeepika Putla - Work - Microsoft Edge & https://mylab.pearson.com/Student/PlayerPractice.aspx?closeUrl=StudyPlanRecommer Analytic Geometry/ Calculus | d Given y =f(u) and u = g(x), find % =f'(g(x))g’ (x)- y:«/U, u=sin x © That's i Correct answe Your answer:
@ study Plan Practice - Rathnadeepika Putla - Work - Microsoft Edge & https://mylab.pearson.com/Student/PlayerPractice.aspx?closeUrl=StudyPlanRecommer Analytic Geometry/ Calculus | ] Help me solve this | A Given y =f(u) and u = g(x) below, . dy y=cosu,u= -x-2sinx Given y =f(u) and u = g(x) below, find ™ = y=cosu,u= -x-2sinx —= Zsinu(ffoSinx)cosx‘ The Chain Rule states that if f(u) is differer (fo g)(x)=f(g(x)) is differentiable at x, and Choose the correct answer below. dy d?y du dy - TS where qu s evall dy dy du dy *p Lo, — i 2 - du dX,where au is evalue d d d X & —y, where l is evaluated ¢ dx du du
@ study Plan Practice - Rathnadeepika Putla - Work - Microsoft Edge @ https://mylab.pearson.com/Student/PlayerPractice.aspx?closeUrl=StudyPlanRecommer Analytic Geometry/ Calculus | ] Help me solve this | A Given y =f(u) and u = g(x) below, y=cosu,u= -x-2sinx Given y =f(u) and u = g(x) below, find ™ = y=cosu,u= -x-2sinx ¢ 17— l:25inu(fxf25inx)cosx o WAy dy e ax = qu Where - - is evaluated ¢ dy du h du ated ax = ax Where - is evaluated ¢ d Giveny=cos u, find fi the derivative of dy . au = sinu du Given u= -x-2sinx. find —, the deriva
@ study Plan Practice - Rathnadeepika Putla - Work - Microsoft Edge & https://mylab.pearson.com/Student/PlayerPractice.aspx?closeUrl=StudyPlanRecommer Analytic Geometry/ Calculus | ] Help me solve this | A Given y =f(u) and u = g(x) below, . dy y=cosu,u= -x-2sinx Given y =f(u) and u = g(x) below, find ™ = y=cosu,u= -x-2sinx — =|2sinu(-x-2sinx)cos x du Given u= -x-2sinx, find e the deriva du - o -1-2cos x d Finally, use the Chain Rule to find ?i dy dy du dx du dx - sinu+(-1-2cosx)
@ study Plan Practice - Rathnadeepika Putla - Work - Microsoft Edge & https://mylab.pearson.com/Student/PlayerPractice.aspx?closeUrl=StudyPlanRecommer Analytic Geometry/ Calculus | ] Help me solve this | A Given y =f(u) and u = g(x) below, . dy y=cosu,u= -x-2sinx Given y =f(u) and u = g(x) below, find ™ = y=cosu,u= -x-2sinx — =|2sinu(-x-2sinx)cos x d Finally, use the Chain Rule to find ?i dy dy du dx du dx - sinu+(-1-2cosx) = —sin(-x-2sinx)+(-1- Therefore, the derivative is =-sin(- dx
@ study Plan Practice - Rathnadeepika Putla - Work - Microsoft Edge & https://mylab.pearson.com/Student/PlayerPractice.aspx?closeUrl=StudyPlanRecommer Analytic Geometry/ Calculus | d Write the following function in the form y = f(u) and u = g(x). Then find ?i as a = {%*5** @ That's il Correct answe Your answer: dyi‘(x3 .
@ study Plan Practice - Rathnadeepika Putla - Work - Microsoft Edge & https://mylab.pearson.com/Student/PlayerPractice.aspx?closeUrl=StudyPlanRecommer Analytic Geometry/ Calculus | d Write the function in the form y =f(u) and u = g(x). Then find % as a function y=csc®x @ That's i (Type an expression using x as the variable.) Correct answe Your answer: g 3 3 » ° 2 3 @ 2 @, o S = @, S 3 c o ] 4 3 < 5 @ j=a @ - (7 )j(;cotxcscx’)J (Type an expression using x as the variable.)