NC Math 4 Module One Assignment Two
.pdf
School
Reidsville High School**We aren't endorsed by this school
Course
MATH 4
Subject
Mathematics
Date
Jan 11, 2025
Pages
2
Uploaded by MasterEnergy15291
Google Doc Access Directions: ● Please click on Filein the upper left corner. ● If you are working on a Chromebook or Google Docs, choose the Make a copy optionand save a copy of the document to your Google Drive. ● If not, choose the Downloadas option and then the Microsoft Word (.docx)option to download an editable copy of the document to your computer.NC Math 4 Module One Assignment Two Directions: There are 3 questions on this assignment, each with multiple parts. Show your work when directed and ask questions if you are not understanding. 1. Piecewise functions are made up of 2 or more functions where each function has a restricted domain. The domain restriction is always written to the right of the function it describes. To evaluate, find which domain the x falls in and use that function to evaluate for that x. If x does not fall within any of the given domains, the function is undefined at that x. Use the piecewise function below to evaluate for each x, which is the number inside the parentheses. Show all work for full credit. a) ________________________ ? − 8() = b) ________________________ ? 4( ) =c) ________________________ ? − 2() =d) ________________________ ? 5( ) =e) ________________________? − 6() =2. Clarence is ordering plates for his friend's birthday party. If he orders 10 or less plates then the price is 2$ per plate plus and a 10$ flat rate shipping fee. If he orders more than 10 plates then the price is 1.50$ per plate and 14$ flat rate shipping fee. a) Write a piecewise function that models this scenario:
b) How much would Clarence pay for ordering 8 plates? Show all work for full credit. c) How much would Clarence pay for ordering 25 plates? Show all work for full credit. 3. Complete the following function compositions using the following functions. Show all work for full credit. ?(𝑥) = 2𝑥2− 3𝑥 + 4?(𝑥)=2 − 𝑥x=1 x=2 x=5 x=8 ℎ(𝑥)-1 0 2 4 𝑘(𝑥)1 2 4 5 𝑚(𝑥)A. ?(?(𝑥))B. ?(ℎ(5))C. 𝑘(𝑚(2))