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Creating Solutions Of Standard Solutions Lab Report

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Creating Solutions of Standard Solutions Jonathan Cody Stewart Gabrielle Wylie Chemistry 1251 section 027 15th October, 2016 Introduction: In this lab, you will first begin by preparing a known amount of Cu2+ by diluting copper (II) sulfate pentahydrate. Dilution is a process in which someone adds an additional amount of solvent to a specific amount of the same solvent; this intern creates a weaker solution. During this experiment you will also be introduced to a Spectrophotometer or Spec 20 for short. By using the Spec 20 you will be engaging in Spectroscopy, which is the technique that is used to find out how much light can pass through a given solution. Throughout this experiment you will hear a few reoccurring key terms such as concentration, …show more content…

The first task of part two was setting the Spec 20’s wavelength for maximum absorbance for Cu2+ which is 600nm. Then begin to find the percent of transmittance for 0.500M, 0.200M, 0.100M, AND 0.050M CuSo4. Then calculate absorbance and graph these values to create a calibration curve. In the third portion of this assignment you must prepare Copper (II) solutions of different concentrations. You first begin by crafting 20.0mL of 0.500M solution from solid (CuSo4)(5H2O) and using the molarity equation you find that 2.5g was the amount of CuSo4 solid. Then place the solid into a medium sized beaker (100mL) and weight it, after weighing the solution one must slightly dilute it by adding H2O. After checking and making sure all the particles were mixed in the cylinder thoroughly, clean the beaker with small amount of distilled water which you will then place small amount of back in the cylinder but being sure to keep its volume under 20mL. Then add small amount of H20 to the mixture using a pipet until it reaches the 20mL mark. Then begin to move the mixture back and forth, when it is done mixing move a small amount to another tube or cuvette and check its transmittance in the Spec 20. From this exact mixture you just created begin to make 20.0mL of 0.200M CuSo4. The same processes will be recreated to form the following mixtures 20.0mL of 0.100MCuSo4 and 20.0mL of 0.050M …show more content…

The Md and Vd stands for diluted molarity and diluted volume. This helped us figure out how to create 0.500M, 0.200M, 0.100M, 0.050M solutions of Copper (II) Sulfate. Molarity (M) = (Moles of Solute/Liters of Solution) Above is the equation for molarity, M which is the abbreviation for molarity is equal to moles of a solute divided by littles of a solution. Moles are then able to be divided by volume in liters of a solution to get finale molarity. A=2 log (%T) Above is the equation for absorbance, A is found when the log of percent transmittance is subtracted by two. This equation was used in all of the absorption equations that were

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