Concentration And Molarity Lab Report
Introduction A way to determine the molar mass of an unknown substance is to use other properties of that substance and solve for desired information. In this experiment, a colligative property, like the freezing point of an aqueous solution of the unknown substance, was used to find the molar mass of the substance. With the molar mass discovered, the identity of the substance was found. Material and Methods First, a Vernier temperature probe was attached to a plastic rod using rubber bands.
The lab started off by measuring critical materials for the lab: the mass of an an empty 100 mL beaker, mass of beaker and copper chloride together(52.30 g), and the mass of three iron nails(2.73 g). The goal of this experiment is to determine the number of moles of copper and iron that would be produced in the reaction of iron and copper(II) chloride, the ratio of moles of iron to moles of copper, and the percent yield of copper produced. 2.00 grams of copper(II) chloride was added in the beaker to mix with 15 mL of distilled water. Then, three dry nails are placed in the copper(II) chloride solution for approximately 25 minutes. The three nails have to be scraped clean by sandpaper to make the surface of the nail shiny; if the nails are not clean, then some unknown substances might accidentally mix into the reaction and cause variations of the result.
The average concentration of my unknown Al3+ solution (#41) was 0.02372 0.00016 mol/ L. My %RSD was 0.67%, which I would say is very good. This means my precision relative to my average was very good. When calculating the mass of the precipitate, my Trial #1 and #2 were both 0.271X, with Trial #3 being 0.27XX.
The purpose of this lab was to determine whether sugar can dissolve in certain solvents. We observed the dissolving rate of 2g of sugar in 50 mL of water, 50 mL of rubbing alcohol, and 50 mL of vegetable oil. It was hypothesized that if the sugar was put in water, it would dissolve faster than if it was put in rubbing alcohol. It was observed that the sugar dissolved in water, but did not in rubbing alcohol or vegetable oil. Therefore, the hypothesis was correct.
Lab Module 12 Sugar and Salt Solutions The aim of my research is to determine the process of dissolution of the compound in water, determining whether a solution to conduct electrical water or does not conduct electricity, knowing ionic or covalent compounds, knowing the result of evaporation when water is mixed with the compound, knowing the number and different concentrations of some solution of the compound when mixed with water, knowing compound will split broke into several moles or divided into multiple molecules. As well as the last to know the salt and sugar compound when placed in water. I will explain about the experiment using Macro. First I'll give you one liter of water, after which I poured salt compound as much as 1.20 mol /
Determination of the molar mass of a chosen compound/element Fran Jurinec 1.M Introduction Molar mass is a physical property of a chemical element or substance which shows the mass per amount of substance. My task is to determine the molar mass of a product substance from one of the following equations: a. Zn(s) + 2HCl (aq) → ZnCl2 (aq) + H2 (g) b. CaCO3 (s) + 2HCl(aq) → CaCl2 (aq) + CO2 (g) + H2O(l) c. Na2SO3 (aq) + 2 HCl (aq) → 2NaCl (aq) + S (s) + SO2 (g)
Although the use of sugar will not be the same for every solution, this would just be something for other tests to be based off of. Another importance of this experiment is to show the effects and properties of supersaturation using crystal growth. Background: To be soluble it means an object or substance can be dissolved, this is especially true of sugar when making rock candy. A solution is a liquid mixture comprised of a solute and a solvent. In this case the sugar is the solute and the water is the solvent, together making up the solution needed to make rock candy.
Research question: In a distillation lab, how do we calculate the number of moles of two pure liquid substances in the initial mixture, distillate samples, and the final mixture? Distillation is a process widely used in chemical research and industrial production. If we need to purify a liquid or extract a liquid substance form another, distillation can be used. Distillation works because different liquids have different boiling points.
Ions produced from substances that are broken down in water are called electrolytes. This solution can conduct electricity by the movement of cations and anions. (http://www.science.uwaterloo.ca/~cchieh/cact/c120/electrolyte.html). This electrically conductive solution is crucial to the wellbeing of a person’s body fluids. This helps with life functions along with other things.
The guiding question, why do the surface area of the solute, the temperature of the solvent mixed affect the rate of dissolution. To answer this question we used three hypotheses to test; if you increase the surface area than the rate of dissolution increases, If you increase the temperature of solvent then the rate of diffusion increases, If you increase the amount of agitation then the rate of dissolution. We predicted that changing the stress, surface area, temperature, and stirring in a controlled experiment it would forward the rate of dissolution. Based on the background on making lemonade, when sugar is added to water and stirred the sugar (solute) dissolves quickly, when sugar (solute) is fine, the temperature is raised, and agitation is increased the solution dissolves at an increased rate.
In this paper, the research conducted will be on the solubility of a solute in a solvent. In everyday situations, solutions are created through solubility. Mixing sugar into our coffee in the morning is and example of solubility, in that we add enough sugar to our coffee to create a homogenous mixture. If more sugar is added to the coffee, to the point of the sugar no longer able to break down, we would no longer have a homogenous solution. Different variables can alter the amount required for a solution or result of a solution, such as temperature and pressure.
Solution is a mixture of 2 or more kinds of molecules or atoms or ions that is homogenous (meaning uniform throughout) 2. Solute is what is being dissolved 3. Solvent is doing the dissolving B: Water’s Unusual Properties 1. Moderating Temperature: Specific Heat A. Specific Heat is the amount of energy required to rise the temperature of a substance 1 Celsius degree C:
Therefore, this experimentation indicated that the sucrose molecules cannot diffuse from the concentration of the dilute solution, while on the other hand the water molecules diffuse from the dilute solution to the concentrated one. Hypothesis: If the (independent variable) sucrose of the dilute solution is
Introduction Solubility is a chemical property that is measured in terms of the maximum amount of solute dissolved in a solvent at equilibrium. The resulting solution is called saturated solution. For example when a sample of sodium chloride solution in water is heated the behavior of the reaction is endothermic obstructing exothermic behavior. Another relationship that can be said about solubility is that the solubility of a solid substance increases as the temperature increases. The solubility of solutes is dependent on temperature.
The components of the sample called solutes or analytes separate from one another based on their relative vapour. This chromatographic process is called elution.
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