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Module 12 Chemistry Lab

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Lab Module 12 Sugar and Salt Solutions The aim of my research is to determine the process of dissolution of the compound in water, determining whether a solution to conduct electrical water or does not conduct electricity, knowing ionic or covalent compounds, knowing the result of evaporation when water is mixed with the compound, knowing the number and different concentrations of some solution of the compound when mixed with water, knowing compound will split broke into several moles or divided into multiple molecules. As well as the last to know the salt and sugar compound when placed in water. I will explain about the experiment using Macro. First I'll give you one liter of water, after which I poured salt compound as much as 1.20 mol / …show more content…

And then with NaNO3 when put into water molecules NaNO3 apart into Na + and NO 3, move in any direction and atomic NO3 collide with atoms of Na + and Cl and see bar of the concentration of molecule concentration of Cl balanced with the N03 - and Na + concentration is higher than the other. And when at the same time yawning occurs is the concentration of Na +, Cl and NO3 ride. And when I add the water that occurs is the concentration of Na +, Cl and NO 3 below. Here I know that the conclusions are the compounds will conduct electricity if the compound is separated into positive ions and negative ions, when administered in water. In addition, the charged compounds will not generate electricity because these molecules can not be separated into smaller molecules and no ions. Then, if the compound solution imposed it concentrated more lights will be bright and if the number of low concentrations of compounds that happened was the lights are not bright. Then the compound was charged ions will separate into small when put in water and compounds which are not so charged shall not separate into smaller ions when put in water. concentration will increase if we evaporate the water and down when we add water. Recently charged compounds will be separated because of the pressure of the water molecule. However, a compound which is not …show more content…

For example, when NaNO3, a salt formed by the reaction of NaOH with HNO3, dissolved in water, the salt is decomposed into: NaNO3 (s) H2O Na + (aq) + NO 3 (aq) Hydrated Na + ions do not give or not also accept H + ions. NO3 ion is the conjugate base of a strong acid HNO3 and has no affinity for the H + ion. As a result, a solution containing ions of Na + and NO3 be neutral, with a pH of 7. In addition, salt can also be made to make bleach. We often use bayclin to whiten clothes. This product contains about 5% NaOCl highly reactive to destroy the dye, so that the clothes be white again. NaOCl salt derived from HOCl (weak acid) and NaOH (strong base). NaOCl + H₂O → Na + +

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