How Is Dr Jekyll And Mr Hyde Ineffective

In The Strange Case of Doctor Jekyll and Mr. Hyde, by Robert Louis Stevenson there are many situations that involve the ineffectiveness and effectiveness of loyalty. Between Jekyll, Utterson, Hyde, and Lanyon the use of loyalty is ineffective, because it led to multiple deaths. Throughout the progression of the novel, loyalty was ineffective because Jekyll could have told Lanyon – his best friend – all of his struggles with Hyde. Lanyon and Jekyll were friends ever since grade school, so Jekyll should know he could have trusted Lanyon with the dark secrets he was facing. When Jekyll had Hyde show Lanyon the transformation from Hyde to Jekyll, Lanyon was so shocked that a few weeks later he died. Instead of showing the transformation to Lanyon, Jekyll could have sat Lanyon down and explained the situation, or he even could have written Lanyon a letter to inform him. If Jekyll told or wrote to Lanyon, Lanyon probably wouldn’t have died of shock, because there would be less of a visual to scare Lanyon to death. Therefore, if Lanyon was aware of Jekyll’s secret, while the secret was taking place, he could have tried to help Jekyll or could have gotten Jekyll help. Because Jekyll kept this secret to

If Poole would have attempted to talk to Hyde, after Jekyll’s orders to obey Hyde as his own master, then he could have sensed something did not seem right about Hyde. Even if it was impossible to find a time to talk to Hyde, Poole could have even used his context clues, and figured out something was wrong about Hyde before things got out of hand. For example, never seeing Hyde and Jekyll in the same place, all of the crimes committed, or Hyde’s name could have been an indicator that something was wrong with Hyde. Again, if Poole would have talked to Hyde or Jekyll, this would have not resulted in the deaths of Jekyll and