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Nt1310 Unit 2 Midterm

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Q2. The reason for the difference in blurring between both the horizontal and vertical lines was due to astigmatism being present. Astigmatism is an off axis aberration which caused the vertical line to appear clearer when observing the USAF target. This occurs when the beam of light converges more rapidly along the tangential direction compared to that of the sagittal direction, thus changing the beam profile from a circular one to a more elliptical one. Because the tangential focus is reached before the sagittal focus, the elliptical beam is compressed into a straight perpendicular line. This made the vertical lines appear clearer and sharper. Therefore the horizontal and vertical lines did not blur equally Q3. The optical quality of an …show more content…

The wavelength of light emitted by sodium light sources is made up of yellow wavelengths from 589.0 - 589.6nm so no colour version is possible. These lights may not be ideal at night time this is because, the human eye cannot function fully in the photopic state, and its colour sensitivity shifts to the scotopic night vision conditions. This phenomenon is known as the Purkinje shift. Herein lies a deficiency of our measure of light because it is based on the normal daylight sensitivity curve of the eye. At very low light levels, one really should to instead rate lamps in terms of their scotopic luminous flux, Due to the Purkinje shift, low pressure sodium lighting becomes less and less efficient at low illuminance …show more content…

The distance between the target and first focal point (fs) of the standard lens were measured to give χ. The focimeter equation〖[F〗_t=F_(s^2 ) x] was used to work out the correct power of the lenses (Ft). A graph was plotted with Ft being the Y value (in dioptres) and χ being the X variable (in metres). Fs2 remained constant. A line of best fit was drawn from the results which gave the power of the unknown lenses. The equation of the line of best fit was[Y = 100x]

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A jump in the points is seen for the cuts above $0.20$~GeV missing energy, as the in-peak pion background from the $\omega\to\pi^+\pi^-\pi^0$ decay is starting contributing above $0.20$~GeV missing energy (see Fig.~\ref{dedp}). The jump is even rigorous for the points above $0.40$~GeV because above that the another in-peak contribution from the $\omega\to\pi^+\pi^-$ decay appeared in the picture (Fig.~\ref{dedp}). %After $0.20$~GeV missing energy, %the background from the $\omega\to\pi^+\pi^-\pi^0$ and $\omega\to\pi^+\pi^-$ decays start %adding up to the peak with increasing $\delta E$. This lead to the overestimation of the reconstructed number and hence the branching ratio.

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You told my partner and I to change the color of things that are different in our papers. Problem Statement: You have a pool table with pockets only in the four corners. If a ball is always shot from the bottom left corner at 45°, and it always bounces at 45° , how many times will it bounce before it lands in a pocket? I worked with a partner, but I spent more time on bigger dimensions and a table of our data, while my partner spent more time on smaller dimensions Pool Table Dimensions Number of Rebounds Corner it lands in(A, B, C, or D) 1x1 0 C 10x10 0 C 2x1 1 B 2x4 1 D 3x6 1 D 2x6 2 C 2x7 2 B 2x8 3 D 8x12 3 B 2x3 3 B 10x6 6 C 30x18 6 C 2x4 8 D 3x8 9 D 4x7 9 B 4x10 9 B 5x7 10 C 7x10 15 D 19x10 25 C 19x20

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Finding Open Source Servers. Turnkey Linux v14.0 is an excellent starting point for First World Bank Savings and Loan. Turnkey Linux will give First World Bank Savings and Loan everything that is needed to begin the process of changing their back end over to Linux.

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Hi all I would like to let all of you know, that all the IT request that you had have been taking care of, I have performed the hardware maintenance to the network and computers and everything should be ok. also, I have been working on meeting the HIPPA compliance for our network and there are some initial points I have been working on 1. I have set up the computer to lock the screens after 5 minutes time of inactivity, this will ensure that computer session are closed when the user is away (is still a good idea to lock the computer every time is not in use) 2. the server room need to have a server shelf or server rack that will keep the It equipment out of the floor.

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Attached is the information you requested. I have been working with RTG on the first two items on the list. The $814.00 was a deduction for a shortage, which they have agreed should be paid. I am waiting for it to show on a check. The $75.00 relates to an invoice difference on freight (driver assistance).

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I began collecting data by contacting the IT technician of Bru-Hims. It was quite difficult to get a response because the IT technician is being deployed out of the office to each health facility on a daily basis. I have gathered a list of questions specifically for the IT technician. Beforehand, I wrote down the questions on a piece of paper before implementing it into Microsoft word. I organised a meeting with them until they finally agreed.

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My original copy of Assignment # 3: Sundus Alhaji- 150 Assignment 3 The Professor’s grading and feedback for Assignment #3: sundus_A3rubric (1) My revised copy of Assignment # 3: Revised Version A Reflection On My Writing Revision After looking at the rubric and analyzing my written assignment, I have noticed that I lack some of the information about ISU being connected to the Reiman Gardens as wells as its mission and vision. Therefore, I supported that missing portion in the fifth paragraph which now focuses beyond the factual descriptions of the organization in itself.

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where $x_i,i=1,2, cdots ,n$ are the states, $underline{x}_i=[x_1,cdots,x_i]^{T} in{R}^i$, $i=1,2, cdots ,n $, $uin {R}$ is the input, and $f_i(cdot)$,$i=1,2, cdots ,n $ are the unknown smooth nonlinear functions which satisfy the global Lipschitz condition. It is assumed that the output $y(cdot)$ is sampled at instants $t_k,k=1,2, cdots ,n$, which represent the sampling instants. $T=t_{k+1}-t_k$ is the sampling interval which is a positive constant. The output signal is available for the observer at instants $t_k+ au_k$, where $ au_k$ are the transmission delays and satisfy $0 leqslant au_k leqslant T$. egin{remark} label{rem:1}

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When observing this image it is apparent to indicate that the

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It has been proven, as I mentioned in my introduction previously, that our peripheral vision is the most efficient way to classify colors in near darkness. The retina encompasses two forms of photoreceptor cells, the rod as well as the cone. The cones are parts that are further delicate when it comes to color, and the rods work best when it comes to motion detection, and are capable to function well in low light environments, and in this case for this experiment, near darkness. The rods are almost totally responsible for our night vision. As the rods are focused throughout our retina, to use them successfully, not viewing right at what you want to see is the best way.

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I noticed that the green and blue lines are curved and creates

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How bright an image will be also depends on how much light is collected by the telescope. The area of the objective lense is

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Refraction: Refraction occurs when light enters a more or less optically dense medium, which therefore has a different refractive index (measure of the velocity light can travel at in the medium compared to in a vacuum in which it can travel at 2.9 x 108ms-1). This causes the light’s speed to increase or decrease, which results in the rays bending towards or away from the normal, so the position of the image formed is dependent on the refractive indices of the two media. For refraction to occur, the light rays have to hit the boundary between media at an angle to the normal (which is 90 degrees to the boundary), otherwise no change in direction will occur, only a change in velocity. Therefore, if the light rays hit the boundary between the different media at a perpendicular (90 degree) angle, they will continue to go straight. This occurs because the angle at which the rays hit the boundary (called the angle of incidence) determines the angle at which the rays will refract (called the angle of refraction).

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The plano-convex lens is replaced with another glass plate and a section of optical fibre was placed between them at one end. Light falling normally on the plates will be reflected back out with a phase difference. Figure 3: Apparatus set up for finding the thickness of an optical fibre, showing the optical fibre between the two glass plates This is due to the fact that some of the coherent light waves were reflected from the top plate and others from the bottom, this path difference resulted in the interference of these waves with one another. This caused an interference pattern similar to the below image: Figure 4: Image similar to the observed interference pattern.

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