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Sodium Chloride Lab Report

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In this experiment, groups were given two different unidentified substances with the goal of being able to figure out what chemical each substance was. Unidentified substance “2” was proven to be Tin (II) Chloride and the Unidentified substance “4” turned out to be Sodium Chloride. The conclusion that substance “2” was Tin (II) chloride could be proven due to the fact that it reacted with Zinc and Sodium Hydroxide. When Tin (II) chloride reacted with Zinc, it began bubbling. This occurred because there was a single replacement reaction between Tin (II) Chloride and Zinc. Zinc is far more reactive than Tin (II) Chloride, making this a very likely conclusion. In the experiment, Tin (II) Chloride should have reacted with the Sodium Hydroxide because …show more content…

Sodium Chloride and Sodium Hydroxide do not produce a reaction with one another, as both of the reactants contain sodium. In a reaction, these two products will stay apart from each other. Moving on, Sodium Chloride Zinc will also produce no reaction. This is because Sodium Chloride and Zinc perform a single replacement reaction. Since Zinc is much less reactive than Sodium Chloride, therefore mixing the substances together will not give you a reaction. In order for a single replacement reaction to work, the lone element has to be more reactive, or higher on the reactivity series, than the element it would be replacing. Because a double replacement reaction occurs between Sodium Chloride and Nitric Acid, one again, there would be no reaction. Double replacements produce two brand new compounds, an aqueous solution, and a substance in a different state of matter. This is caused by two compounds trading cations or anions to create two new compounds. Because two soluble chemicals are incapable of reacting with one another, the “Solubility Chart” must be considered when dealing with double replacement reactions. Since there is not reaction between Sodium Chloride and Nitric acid, as well as the other two chemicals, the conclusion that Sodium Chloride is what Substance “4” consists of

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c) Copper (II) Nitrate is the most reactive (#1). Zinc Nitrate is second most reactive (#2). Magnesium Nitrate is the least reactive (#3). d)It is the in the opposite order.

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The lab started off by measuring critical materials for the lab: the mass of an an empty 100 mL beaker, mass of beaker and copper chloride together(52.30 g), and the mass of three iron nails(2.73 g). The goal of this experiment is to determine the number of moles of copper and iron that would be produced in the reaction of iron and copper(II) chloride, the ratio of moles of iron to moles of copper, and the percent yield of copper produced. 2.00 grams of copper(II) chloride was added in the beaker to mix with 15 mL of distilled water. Then, three dry nails are placed in the copper(II) chloride solution for approximately 25 minutes. The three nails have to be scraped clean by sandpaper to make the surface of the nail shiny; if the nails are not clean, then some unknown substances might accidentally mix into the reaction and cause variations of the result.

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Throughout the experiment, copper was altered a total of 5 times, but after the final chemical reaction, solid, elemental copper returned. Each time the solution changed color, a precipitate formed, or when gas appeared, indicated that a chemical reaction was occurring. For the first reaction, copper was added to nitric acid, forming the aqueous copper (II) nitrate (where the copper went), along with liquid water, and

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Discussion A chemical reaction did occur in every combination, however no signs were shown for combination d) between sodium chloride and potassium nitrate. Indications of a chemical reactions occurring between these two compounds were not present, as in the colour did not change, and gas, heat, light nor sound was produced. In addition, when sodium chloride and potassium nitrate combine they form sodium nitrate and potassium chloride. The products sodium nitrate and potassium chloride are both aqueous, therefore no precipitate was formed either.

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