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Cellular Respiration Lab Report

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An experiment was conducted in order to determine the oxygen consumption in dry and soaked peas within two different temperatures of water. Cellular respiration is the release of energy by metabolic chemical oxidation in the mitochondria, (DeStefano 2016). The hypothesis was the germinating warm water peas would have the highest rate of oxygen consumption. Within this experiment, a twenty-one degree celsius bath and a six degree celsius bath were set up. Then, a one hundred mL graduated cylinder was filled with fifty mL of water. Twenty-five germinating peas were then placed inside. The amount of water displaced was then determined and recorded; and the peas were removed and placed on a paper towel. This procedure was repeated with glass beads …show more content…

Cellular respiration can be measured by the consumption of oxygen, the consumption of carbon dioxide, and the release of energy during cellular respiration. Within the experiment conducted, the relative volume of O2 consumed was measured into different temperatures within germinating and nongerminating peas, (DeStefano). Fluids and gas flow from regions of high-pressure to regions of low-pressure this carbon dioxide produced during cellular respiration will be removed by potassium hydroxide and will form a solid potassium carbonate. Due to the removal of carbon dioxide, the change in the volume of gas in the respirometer will be directly related to the amount of oxygen consumed. In this experiment using a respirometer, the scientists were able to measure the amount of oxygen being consumed in relation to how quickly the peas were respiring. Hypothesis If the germinating and dry peas are submerged in baths of water for twenty minutes, then the germinating peas will consume the most oxygen over dry peas. The warmer the temperature surrounding the vials, the faster the rate of oxygen consumption will be due to them requiring a more extensive output

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Additionally, it was difficult obtaining a piece of rhubarb that was thin and particularly red, therefore the effect could not be best observed in the cells. Part B: Design your own experiment Parts of this practical were taken and slightly altered from the following link http://www.markedbyteachers.com/gcse/science/investigate-the-effect-of-surface-area-on-osmosis-in-potato-tissue.html Aim: To observe the effect different surface area: volume ratios have on osmosis in potato tissue. Hypothesis: If the potato has a larger surface area: volume ratio, the quicker osmosis will take place and the larger the mass will be at the end of the experiment, therefore the difference in mass of the potatoes from the start of the experiment to the end of the experiment will be larger. Additionally, the potato pieces left in a saltwater solution will decrease in mass, whereas the pieces left in water will increase in mass.

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As stated in the background of the lab, "seeds are considered to be in a period of dormancy, where they metabolize stored energy at a very slow rate while the seed is still considered alive" (Hands On Labs). During germination, the developing plant embryo uses the stored food supply in the seed for cellular energy and growth. Thus, cellular respiration is taking place as the seeds grow. Without water the seeds cannot begin germinating thus the seeds in test tube N did not undergo photosynthesis(Hands On Labs). B. Were the seeds in the “G” tube undergoing both photosynthesis and respiration, only photosynthesis, or only respiration?

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We soaked over 15 beans with the knowledge that the beans could split again after being soaked. After the soaking process was complete six beans were chosen for planting. In preparation for planting, two 8 oz. plastic cups were utilized for the control and experimental groups.

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Because carbon dioxide is absorbed by the plant during photosynthesis less carbon dioxide present in the chamber is a sign that photosynthesis is working. The four lights used for this experiment range across the light spectrum on both sides in order to test a wider variety of wavelengths. All lights will be placed directly on the spinach leaf at the same distance so as not to give any spinach leaf a different light intensity, which could affect the data. This experiment will be able to show which light, ranging across the light spectrum, will allow the Spinach to perform photosynthesis more efficiently.

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A possible explanation for why there was no mitochondrial activity observed in the boiled corn kernels might be because increasing the temperature would disintegrate dehydrogenases and thus they wouldn't function as efficient or they

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For this lab I will be using water and sucrose to demonstrate the rate of osmosis. In this lab I will be exploring how temperature impacts the rate of osmosis by placing pieces of potato of equal size in solutions of different temperatures and observing the change in mass of potato after a given period of time. The change in mass will indicate the rate of osmosis.

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Oxygen presence and availability will differentiate which type of cellular respiration will be used. In aerobic respiration it will involve the oxygen to produce energy needed for the cells to work in the form of adenosine triphosphate (ATP). This includes water and carbon dioxide being the by-products. However if oxygen is not present it will be anaerobic respiration, where the cells are still able to produce the energy that’s needed but a lot less amount.

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In order for cells to produce ATP, a source of energy found in every cell, they must respire. Cellular respiration is a process in which cells break down organic substances in order for energy to be released, which in turn generates ATP (Upadhyaya, 2018). ATP is essential for a cell's life, which is why cellular respiration must occur persistently (Upadhyaya, 2018). The equation for cellular respiration is C6H12O6 + 6O2 í 6CO2 + 6H2O + energy (~36 ATP)

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For any seeds that did not germinate, the seed length was measured and used towards the data. The plant heights were put into a data table and a mean was found for each level of I.V. for further data analysis. Then, all of the steps from placing the seeds into the microwave to adding the plant lengths together for the final data, including those two steps, were repeated four more times for a total of five repeated trials. Next, all of the steps from placing the seeds into the microwave through the step preceding this one, including those two steps, were repeated for a total of five repeated trials for all remaining levels of I.V., excluding the warm water level(100W for zero seconds, 500W for 30 seconds, 900W for 30 seconds). Finally, all of the plant lengths, including those that did not germinate, were added together for the final

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By using the same mass of potato slices and putting them in different concentration of solutions for a specific amount of time will tell us how the concentration changes the mass of the potato slice. Therefore changing the rate of osmosis. Hypothesis: I predict that, if the piece of potato was put into a solution that has a high concretion of sucrose then the potato slice would lose mass as it would lose water from its cells because the water is moving out of the cell from a high concentration to a low concentration of water through a semi- permeable membrane. The cell is hypotonic and the solution is hypertonic.

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However, our experiment was to test if the amount of water used to water each crop was unnecessary. We watered a group of plants with the average amount of water used in farms, watered a group of plants with a little less than average, and watered a group of plants with a small amount of water. We normally watered the plants with the average amount until all of the plants germinated. After the plants germinated, we started our experiment and controlled the amount of water. After about two weeks our experiment was over.

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Exercise Intensity on Cellular Respiration measured through Heart Rate and CO2 Production Background Research Cellular Respiration: C6H12O6 + 6O2 >>> 6H2O + 6CO2 + 36 ATP When examining the effects of exercise on cellular respiration, we can assess three main bodily functions: carbon dioxide production, heart rate and breathing rate, all telling us of an increase in cellular respiration. We can only directly measure the CO2 output that is a direct result of cellular respiration, we can use all of these fields of measurement to show that exercise uses more or less energy than rest, answering the question. Cellular respiration takes one glucose or sugar (C6H12O6), and six oxygen (6O2) to produce 36 ATP, essentially units of energy and release

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Breathing is the transportation of oxygen across from the air in the lungs to circulating red blood cells (erythrocytes) which pass on the oxygen onto cells which require and utilise the oxygen, during aerobic respiration, to produce energy in the form of ATP. This biochemical reaction produces carbon dioxide as a waste product, and it is transported, using the red blood cells (RBCs), back to the lungs and exhaled. Figure 1 shows the relationship between breathing and cellular respiration, with the two connected by the gas carrying red blood cells. Notice the requirement for oxygen by the cells to produce energy in the equation at the top – breathing is how this requirement is fulfilled, whilst venting the waste products from respiration

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1950 Words | 8 Pages

Background Information: In this experiment I will be investigating the impact of light intensity on the rate of water uptake, due to transpiration, by attaching a shoot from a leafy plant in the capillary tube of a potometer, and then measuring how long it takes for a bubble to move a set distance. The faster the bubble moves, the greater the rate of transpiration. I will be placing one plant in an environment where it is exposed to high-light intensities, and another plant in an environment where it is exposed to low-light intensities. Transpiration is the process of the transport of water and nutrients up the the plant from the roots to the leaves.

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Introduction Cellular respiration - the process to make energy and fuel life processes - creates a constant demand for oxygen and elimination of carbon dioxide. This is carried out in the gaseous exchange system. The gases first dissolve (in the fish and mammals) and then diffuse (in mammals, fish and insect) through a moist and thin, (thickness of a cell) semi-permeable membrane with a large surface area to volume ratio. Dissolved gases are transported by a circulatory system (in mammals and fish) to cells in the body. In insects, oxygen and carbon dioxide are transported directly to each individual cell.

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