3. Upon adding 20 drops of NaOH, a white precipitate was formed signifying acidic impurity. In the second NaOH mixture, about 20 drops were administered and no precipitate formed indicating that the ample is more pure than before. Data: Weight of flask = 75.10 grams Weight of the flask with solids =
Introduction: The aim of this experiment was to see whether water, Powerade or orange juice contained more electrolytes. Electrolytes are responsible for controlling the total amount of water in the body, regulating blood volume and maintaining muscle and nerve function. A lack of these electrolytes can cause headaches, fatigue, confusion, hallucinations and muscle spasms. I found that water and distilled water were less conductive than the orange juice and Powerade and orange juice proved to be the most conductive.
If the ion is in solution, NaOH can be added and if a blue precipitate is formed the metal ion is copper (1). A flame test can also be used to identify the metal ion. Copper burns blue-green (1) and iron burns gold (3). A quantitative test can be used to then determine the charge of the metal ion.
Procedures In this experiment, an unknown mixture was given, that contained both sodium bicarbonate(NaHCO3) and sodium chloride(NaCl). The purpose of this experiment was to find the percent (%) composition of the sodium bicarbonate and sodium chloride in the unknown mixture. Hydrochloric acid(HCl) and a scale were materials that were also used during the lab.
A 0.2057 M stock solution of NaOH was added to the plastic syringe while the acidic solution was being made. 1.329 g of unknown acid P was weighed on the electronic scale and recorded. The unknown solid acid was placed into a 100 mL volumetric flask and filled to the line with a 0.1 M stock solution of KCl. The solution was agitated to aid in the dissolving of the solid acid solution. When the acid was completely dissolved 25 mL of distilled water was added to a clean 100 mL beaker, along with 25.00 mL of acidic solution using a volumetric pipette.
Goals The primary goal of this experiment was to identify an unknown compound by running various tests to determine the qualitative solubility, conductivity, and pH value of the compound. Tests were also performed for the presence of specific cations and anions in the compound. The second goal was to discover the reactivity of the unknown compound by reacting it with different types of substances. The third goal of this project was to calculate the quantitative solubility of the unknown compound in water.
Each buffer was measured in a 100 mL graduated cylinder and contained in a 40 mL beaker. Once the reading of the buffer was stabilized, the program entered into reading 1. The probe was cleaned with distilled water and dried before being placed into the second buffer for reading 2. Once the second calibration was completed the pH probe was cleaned again. Next the probe was placed into the unknown solution.
In the experiment they used probes to test for pH, dissolved oxygen, total dissolved solids, conductivity, and turbidity. The probes hook up to the computer and collected the averages for each test. They collected this data and used it for later evaluation of the contaminates. They also tested for iron, copper, and chlorine with different tablets.
Procedure and Observations To begin the lab, first all the correct equipment and materials had to be collected
Explain the relationship between the ionisation of amino acids and pH |Structural diagram of the neutral structure| |Structural diagram of positively charged structure| |Structural diagram of negatively charged structure| Explain how the form of an amino acid, whether positively charged, negatively charged or neutral, depends of the pH of the solution ? If you increase the pH of a solution of an amino acid by adding hydroxide ions, if this is done then the hydrogen ions will then be removed from the -NH3+group . . To test if it is now a negative ion a process called electrophoresis.although it is colourless its position can be detected using ninhydrin. If the amino acid has dried and then heated gently it would appear as
The negatively charged protein molecules (A-) inside the neuron cannot cross the membrane. In integration to these selective ion channels, there is a pump that utilizes energy to move three sodium ions out of the neuron for every two potassium ions it inserts. Conclusively, when all these forces balance out, and the difference in the voltage between the inside and outside of the neuron is quantified, have the resting membrane potential. The resting membrane potential of a neuron is about -70 mV (mV=millivolt) - this designates that the inside of the neuron is 70 mV
Since equilibrium cannot be reached, an electrochemical driving force is generated which acts on the ions. It is derived by finding the difference between the membrane potential obtained and the equilibrium potential expected. The sign of the value of this force decides the direction of movement of ions. Since we have cations (positive ions), a positive value shows movement of ions outside the cell membrane and a negative value shows movement of ions inside the cell membrane. If the value is equal to that of the equilibrium potential, the driving force acting on the ion is 0.
A clean 250-mL beaker was taken and around 0.3 to 0.5 g of potassium acid phthalate was weighed into it. 50 mL of distilled water was approximately added to this 250 mL beaker and gently swirled so that the solid (potassium acid phthalate) got fully dissolved into the water. 2 drops of phenolphthalein indicator solution was added to the beaker. The pH electrode was calibrated using the pH buffers.
This experiment has to be carried out carefully
The dependent variable is the rate of decomposition of water which is measured by the volume of hydrogen gas and oxygen gas in cm3 The independent variable is the voltage here as I increase it from 9-14 Room temperature was 24 rtp and I carried out the whole experiment in the same room. If the temperature increases the rate of electrolysis will increase. The concentration of the sulphuric acid which is 0.02 M. If I increase the concentration of sulfuric it would’ve been the decomposition of sulfuric acid not water because we just need some ions in the pure water so the ions can move to the electrodes.