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Cmt1310 Unit 4 Assignment 12

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Benjamin Crowley Champlain College CMIT-135-45 Week 4: Assignment 4 #18 When keeping in mind that MIPS stands for Million Instruction Per Second, 500 MIPS comes out to 500 million instructions per second. Since the question states that 56,000 bits over a second the transfer time would be 1/56000. 500,000,000*1/56,000= 8928 instructions per bit #19 a) Since the code contains 6 bits and each machine language contains 2^n the number would be 64. b) The maximum size of the memory on the 18 bit machine is 2^18 =262144 c) 8 bits is equal to 1 byte, therefore each operation requires 48 bits. #3 A program written in assembly language is the source program, which would be the English letter. Since the object program is the corresponding language,

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