A way that you can figure it out is by adding ⅖ to ⅓ you can do that by adding the top to which is 2+1=3 so that would be your numerator usually for the bottom it would stay the same if they both have the same denominator but since it is not the same you have to add those to
The value provided as the result of a function call. Code that is used during program development to assist with development and debugging. "Function Composition" is applying one function to the results of another. Some functions can be de-composed into two (or more) simpler functions. Assume that the center point is stored in the variables xc and yc, and the perimeter point is in xp and
METHOD: The following procedure was taken from the 2017 Millsaps College lab manual.1 The experiment was split into two parts, part A and part B. Part A was to find the heat capacity while part B determined the specific heat of an unknown metal. This was the final goal of the lab. To start, a temperature probe had to be connected to a LabQuest2 data collection device. 100.0 mL of deionized had to be added into a Styrofoam cup.
∫▒〖x^2 (〖2x〗^3-1)dx〗 2. ∫▒(x+1)dx/∛(x^2+2x+1) 3.∫▒(2x+3)dx/(x^2+3x+4) 4. ∫▒((〖(x〗^(1/3)+1)^(3/2) dx)/x^(2/3) 5.∫▒〖sec x dx〗 6.∫▒ 〖e^4x dx〗 7. y dx – x2 dy = 0 8. (1 + x2) = dy/dx y3 9. dy/dx=
I can interpret that if a snail is presented with both leaves then it will only eat the plain leaves and not the striped leaves. It doesn’t eat the striped ones because it knows that a clover that can produce cyanide is striped and therefore poisonous, so it tends to stay away from it. That’s why the snail didn’t eat the clover the plain leaf that was painted with white stripes. From the wild it knows not to eat striped leaves. It’s pretty much like a visual warning.
Procedures In this experiment, an unknown mixture was given, that contained both sodium bicarbonate(NaHCO3) and sodium chloride(NaCl). The purpose of this experiment was to find the percent (%) composition of the sodium bicarbonate and sodium chloride in the unknown mixture. Hydrochloric acid(HCl) and a scale were materials that were also used during the lab.
Of course, the various sources of error have affected the results from this lab. Since the initial mass of eggs used was different for each group, the experimenters had to find the percent change in mass to keep the results constant. To conclude, when the eggs were placed in a corn syrup solution with more solute, their masses steadily decreased. The inside of the eggs have a lower solute concentration than the corn syrup solution outside the cell. Water within the eggs flow outwards through the membrane to the syrup solution, decreasing the solute concentration.
Use the slide presentation to answer the following questions about the atmosphere. Question Answer What is the atmosphere?
Elijah Brycth B. Jarlos IX-Argon 1. Multicellularity is a condition of an organism to have multicellular cells. An example of a organism who has multicellular cells are plants, animals, and humans. The main reason of why scientists have a hard time finding a good set of existing organisms to compare. Is neither the first set of organisms which is being compared is dying as fast as the second specimen is being examined or they just can’t find the right species.
Stoichiometry is a method used in chemistry that involves using relationships between reactants and products in a chemical reaction, to determine a desired quantitative data. The purpose of the lab was to devise a method to determine the percent composition of NaHCO3 in an unknown mixture of compounds NaHCO3 and Na2CO. Heating the mixture of these two compounds will cause a decomposition reaction. Solid NaHCO3 chemically decomposes into gaseous carbon dioxide and water, via the following reaction: 2NaHCO3(s) Na2CO3(s) + H2O(g) + CO2(g). The decomposition reaction was performed in a crucible and heated with a Bunsen burner.
This lab’s end result was to correctly identify each unknown solution using prior knowledge of chemical properties and the results of the first experiment conducted. Unknown solution D was the only colored solution, being blue while the others were clear. This made it easy to then match D up to Copper Sulfate because of its color. As unknown A and B were added together, lots of gaseous bubbles formed and revealed the fact that that reaction was the reaction between Hydrochloric Acid and Sodium Carbonate because it was the only reaction that produced a gas release. Unknown A and C produced the only yellow, brown precipitate just as the reaction between Sodium Carbonate and Silver Nitrate had previously.
This is done by logging evidence mathematically and anecdotally on cumulative records. The differentiating function. Once their
Empirical Formula of Magnesium Oxide - Lab Report Background Information/Introduction: The aim of this lab is to determine the empirical formula of magnesium oxide by converting magnesium to magnesium oxide. As an alkali earth metal, magnesium reacts violently when heated with oxygen to produce magnesium oxide and magnesium nitride as a byproduct. In order to obtain only magnesium oxide, distilled water was added so that magnesium nitride will react and convert to magnesium hydroxide. Further heating then oxidizes all of the magnesium into magnesium oxide.
Math Analysis For math this year I chose to do 8th grade math on Khan Academy. I had done Khan when I was homeschooling so it was a pretty obvious choice. I did 7th grade math last year
Properties of Substances Express Lab 1)The purpose of this lab was to compare the physical properties of different types of solids and how the properties of solids are determined by their intermolecular forces and their intramolecular bonds. Then we were to classify each type of solid as either ionic, metallic, non-polar molecular, polar molecular, or network. Paraffin wax classified as a non-polar molecular, Silicon dioxide was classifies as a network, Sodium chloride was classified as ionic, Sucrose was classified as polar molecular and Tin was classified as metallic. (2)The intermolecular forces that are present in Paraffin wax are dispersion forces, because it is non-polar and carries a negative charge. Followed by Sucrose that has