On October 6, 2016, our environmental science class explored biodiversity. We conducted a lab involving the biodiversity of cars in two parking lots that are at our school. We used the parking lots as "communities" and the make of each car in a specific parking lot a "species". We classified the parking lots into Community A and Community B. Community A represented the athletic parking lot and Community B represented the band parking lot, both lots hold students and factuality cars. Our class split in half, one group attained data for Community A while the other attained data for Community B. We acquired our data by counting and writing down the make of each car in the parking lot. After this each group tallied the same "species" together …show more content…
Then the groups used the data from each community to find the species richness, evenness, dominance, relative diversity, and the Shannon-Weiner Index for of that particular community. The diversity measurement table shows the reader the comparison between Community A and Community B. In Community A there were 49 different species and in Community B there were 40 different species. The groups configured this information by plugging in the data from each community into the equations, H= -sum(Pi In [Pi]) and E= H/In(R). (H) being the uncertainty of predicting a species, (Pi) being the relative abundance, (E) being the evenness, and (R) being the species richness. By the results of equation we could determine the evenness, relative diversity, and the Shannon-Weiner Index of each community. The species richness is how many species there are in a certain community, it does not mean how many individuals there are. The evenness of community is calculated with the equation E= H/In(R). The dominance of the community is based upon which species had a higher population than the rest. The relative diversity is based off of the Shannon-Weiner Index, if the answer is less than or equal to 3.2 it is a low diversity and if it is higher it is a high diversity. The Shannon-Weiner Index is calculated with the equation H= …show more content…
Community B has the fewer amount of species and number of individuals in its population between the two communities. The result of a lower population of species could be because of pollutants produced by humans. This could have harmed the environment in which the species lived, so much, not a large amount of species can adapt/live there. Also, the humans could have destroyed habitats and homes of the species that the species can no longer live there because they have no shelter. Humans can destroy habitats by deforestation, construction,