ANSWER: When the amount of enzyme is increased the reaction rate is increased. The liver contains the enzyme catalase that eliminates the hydrogen peroxide to break it down the oxygen and water. 2. Is there a “control” (control group or control sample) in this experiment? What is it? Review the concept of a “control” in experimental design if necessary. ANSWER: Yes there is a controlled group and it is in test tube A. 3. What information does this control provide? ANSWER: When there is no enzyme present, there is no reaction, 4. Why do we add water to some of the test tubes in this experiment? ANSWER: Water helps with enzyme solidity and helps promote high performance for a reaction rate. PART A – QUESTIONS: 5. Create …show more content…
3. (a) What effect does an extreme high temperature have on enzyme function? (b) What is the cause of this effect, in other words what exactly happens to the enzyme molecules due to extreme high temperature? Explain your answer in detail and supported by research. ANSWER: In the higher temperature the enzymes in the liver were being broken down from the meat being cooked and making the enzymes nonreactive. 4. What happens to the liver homogenate when you cool it back down to room temperature and add more hydrogen peroxide? ANSWER: Once the enzymes were nonreactive and broken down, they did not respond to the hydrogen peroxide. PART B – QUESTIONS: 5. Create a bar graph describing your observations of the effect of temperature on catalase activity. All parts of a graph should be properly labeled or identified, including a short descriptive title for it Label the “x” and “y” axes with a brief description and identifying their measurement units properly. Your graph must be completely clear for anyone. You may lose points if anything in your graph is incomplete or unclear. Insert your graph in the space