ipl-logo

Calculating The Slope Lab Report

779 Words4 Pages

Calculating the Slope
Slope = y2 - y1x2-x1 = 57.47 - 18.7460 - 20 = 38.7340 = 0.96825 g/mL
The density graph has been based off all the information in the chart above. All the specific volumes and masses were recorded in this graph, in order to help compare the two and see the difference. In addition to this, a trendline was added in order to calculate the slope of the line. The slope line is a representation of the change in density overtime. More specifically, it shows the change of value in the mass of the water per the change of volume. The equation used to calculate the slope was y2 - y1x2-x1 . The values of each were replaced with 57.47 - 18.7460 - 20 - the numerators are the corresponding mass to number located under (e.g. the mass …show more content…

Looking at this value, and comparing the experimentally determined values, the values do not exactly match up, but are close together, as the values are only 0.4 - 0.6 g/mL away from the value of 1 g/mL. One reason why the values may not match up is because of the amount of liquid used. Sometimes, the value of water poured into the graduated cylinder may not be equal to specific volume which was to be used. In order to improve that, making the water volume more precise may allow for more accurate results. Secondly, the type of water used may of affected the value. If we take a look at pure water, the value of it at room temperature is 0.99823 g/mL. If we use this water (by boiling it before hand), and confirming the density is equal to the accepted value, than it will increase the chance of being more accurate. Another reason as to why I suggest this is because tap water may have other substances or little things mixed, which may cause an inaccurate reading of the mass which will cause an error in density, so it is better to use pure water. Finally, temperature may play a big role in this as well.The accepted room temperature would the density of 1g/mL is 21°C. If the room temperature is measured, then it can be considered that there will be a change in density due to an increase or decrease in the average room

Show More
Related
886 Words | 4 Pages

To graph population or disease, we needed to use exponents; in equation-form, the exponent was an X, but it could be substituted for any number, which would represent the year. You would also find the current population or number of cases and divide them by the amount the previous year (the starting number) and add that to one to find the rate, which would show you if it was growth or decay. Finally, you use the starting number as your constant or y-intercept. If you were trying to graph the decay of a population, the equation could be: y=150,000(1.5)x; if you were trying to graph decay, the equation could be: y=150,000(0.5)x. You can replace X with any number (number of years) to find the population in the future (positive number) or in the past (negative numbers).

Read More
496 Words | 2 Pages

In this week’s lab we had to determine the density of a quarter, penny, and dime. My question was “How does is each coin?” Density is the amount of mass in an object. To find the density of each coin in this lab, we used a triple beam balance to find each coin’s mass and a graduated cylinder to find their volumes. With all this information, I can now form a hypothesis.

Read More
531 Words | 3 Pages

The equation is f(x+h)-f(x)/h. This formula finds the slope of the sectant line that goes through two points that are on a graph of f. These are the points with x- coordinates x and x+h. It also allows you to find the slope of any curve or line at any single point. The difference between this and the slope formula is y is used as the y-axis, but in the difference quotient, the change in the y-axis is described by f(x).

Read More
472 Words | 2 Pages

WHAT HAPPENED? The taller the starting ramp height was, the greater the distance the plastic container rolled up the ramp. When the height of the starting ramp was 0 cm (the control group), the average distance the container climbed up the ramp was 0 cm.

Read More
1237 Words | 5 Pages

(0.01 moles of NaOH) x (1 mole Ca(OH)2/ 2 moles of NaOH) = 0.005 moles of Ca(OH)2 Tube 1: (0.0020 moles of CaCl2) x (1 mole Ca(OH)2/ 1 mole of CaCl2) = 0.002 moles of Ca(OH)2 (0.002 moles of Ca(OH)2) x (74.08 grams/mole) = 0.1 grams = theoretical yield Tube 2: (0.0035 moles of CaCl2) x (1 mole Ca(OH)2/ 1 mole of CaCl2) = 0.004 moles of Ca(OH)2 (0.004 moles of Ca(OH)2) x (74.08 grams/mole) = 0.3 grams= theoretical yield Tube 3 (0.0050 moles of CaCl2) x (1 mole Ca(OH)2/ 1 mole of CaCl2) = 0.005 moles of Ca(OH)2 (0.005 moles of Ca(OH)2) x (74.08 grams/mole) = 0.4 grams =theoretical yield Tube

Read More
1161 Words | 5 Pages

The data was handled accurately, values clearly labeled and calculated in the correct procedure. The procedure of reacting magnesium with oxygen was most likely the source of error. It is possible that the magnesium strip had not completely reacted with oxygen yet when I took the crucible off the burner and dropped distilled water into it.

Read More
1274 Words | 6 Pages

In this lab we used two processes called Diffusion and Osmosis. Diffusion is the movement of molecules from areas of high concentration to areas of low concentration. Diffusion is a process that requires no energy and involves smaller non-polar molecules. In Figure 1 you can see the molecules spreading throughout the glass from the area of high concentration, so that the areas with low concentration are filled evenly as well. The other process was osmosis.

Read More
320 Words | 2 Pages

By counting the difference of the vertical direction (rise) and the horizontal direction (run) then take the ratio of the rise over run to find the slope of the line , which should be the m in the y= mx+b

Read More
630 Words | 3 Pages

Introduction The intent of this experiment is to understand how hot and cold water interact with each other by combining clear hot water and black ice cold water. I hope to learn more about how hot and cold water interact with each other. As of now, I know that cold water is denser than hot water. Knowing this I formed my hypothesis.

Read More
1649 Words | 7 Pages

Lab 2: Force Angle relationship 250 words 4 marks In this lab we concentrated on investigating the relationship between joint angle and consequential ability of muscles to produce force. The knee joint was focused on with the quadriceps (rectus femoris, vastus lateralis, vastus intermedialis vastus medialis) and hamstrings (semitendinosus, semimembranosus. biceps femoris lomg head and short head) being the main muscle groups studied.

Read More
1001 Words | 5 Pages

IV. Data and observations Mass of beaker (g) 174.01 Mass of beaker + NaOH pellets (g) 174.54 Mass of NaOH pellets 0.53 TRIAL 1 TRIAL 2 Mass of potassium acid phtalate (KHP) (g) 0.15 0.15 final buret reading (ml) 30.75

Read More
1101 Words | 5 Pages

* A * ρ * v2) FD: Drag Force Cd: Drag Constant A: Area ρ: Density of Fluid v: Flow Velocity relative to Object Instrument to measure Drag: Force Balance Speed: Similar to surface it is also included in the equation and is directly proportional to Drag force. Fluid Density: Increased density means an increase

Read More
603 Words | 3 Pages

In this experiment, the amount of water lost in the 0.99 gram sample of hydrated salt was 0.35 grams, meaning that 35.4% of the salt’s mass was water. The unknown salt’s percent water is closest to that of Copper (II) Sulfate Pentahydrate, or CuSO4 ⋅ 5H2O. The percent error from the accepted percent water in CuSO4 ⋅ 5H2O is 1.67%, since the calculated value came out to be 0.6 less than the accepted value of 36.0%.This lab may have had some issues or sources of error, including the possibility of insufficient heating, meaning that some water may not have evaporated, that the scale was uncalibrated, or that the evaporating dish was still hot while being measured. This would have resulted in convection currents pushing up on the plate and making it seem lighter by lifting it up

Read More
864 Words | 4 Pages

Due to the unaccountability of the inconsistency in droplet size, many of the numbers may be varied because in one trial a huge droplet may count as one, but in another trial, I may have counted a small droplet as one, which causes results to possibly be

Read More
3578 Words | 15 Pages

With this small change (by 51.4 seconds), it can be concluded that there is a relationship between the different temperatures of sodium solution and the time it takes for the ice cube to melt in the sodium solution. The raw data graph also has a c or the y intercept of 64.24 seconds and the R2 value is 0.97281. R2 value is a fraction between 0.0 and 1.0, and has no units. An R2 value of 0.0 means that knowing X does not help you predicts Y. There is no linear relationship between X and Y, and the best-fit line is a horizontal line going through the mean of all Y values.

Read More

More about Calculating The Slope Lab Report

Related Topics

Open Document