In Tube A with the water snail, cellular respiration is being undergone. Tube B, is a aquatic plant so, for this tube, photosynthesis is most likely happening. Tube C has both the water snail, and the aquatic plant which means there is going to be an equilibrium of both processes being the photosynthesis, and cellular respiration. Tube D is the control. BTB or bromthymol blue is a solution used to detect changes in pH. The detection of pH is associated with the amount of CO2 present, meaning that the pH changes with the amount of CO2. The color spectrum ranges from blue to yellow, which means green is equilibrium. Photosynthesis takes in carbon dioxide which makes the solution less acidic and the color blue. Cellular respiration does the opposite by releasing CO2 from the broken down glucose. Therefore, the BTB solution turns from blue to yellow. So, in tube A the snail is going through cellular respiration releasing CO2 and making the …show more content…
This is because photosynthesis is not taking place without sunlight. Without sunlight the plant can't power CO2 and Water to produce Glucose and Oxygen. However, organisms are always undergoing cellular respiration otherwise whatever the organism is it'll usually end up dead. So, tube A will be yellow since the snail exhales CO2. Tube B will be a lighter blue possible because the plant has most likely already undergone photosynthesis to grow before hand. Especially since the experiment states that it was a healthy plant, whereas a yellowish, drooping malnourished plant would not be able to provide sufficient data. So for the time being it'll take in CO2 until it stops functioning without the sun. Tube C would also be yellow because there is no longer equilibrium once the plant runs out of initial energy from it's previous lit environment(before being used for the experiment). Tube D will not change because there is nothing with get the blue